follow up to yesterday Suggested Proofs follow up to yesterday06 months agoIsaacreviewed1AttachmentI am also adding a follow up …
hmmm it should be … n+\cfrac{1}{n+1+\cfrac{2}{n+2+\cfrac{3}{n+3+\cfrac{4}{…}}}}=\frac{\frac{1}{n!}}{e-\sum_{k=0}^{n}\frac{1}{k!}} i forgot to write n , n+1 , n+2 etc … Reply
hmmm it should be …
n+\cfrac{1}{n+1+\cfrac{2}{n+2+\cfrac{3}{n+3+\cfrac{4}{…}}}}=\frac{\frac{1}{n!}}{e-\sum_{k=0}^{n}\frac{1}{k!}}
i forgot to write n , n+1 , n+2 etc …